使用PHP获取字母表中前一个字母的最有效方法

Question

Its working nicely:

$str = 'a';
echo ++$str; // prints 'b'

$str = 'z';
echo ++$str; // prints 'aa' 

Its very useful to get next column name in an excel file.

But if I use similar code using -- operator to get the previous letter then its not working:

$str = 'b';
echo --$str; // prints 'b' but I need 'a'

$str = 'aa';
echo --$str; // prints 'aa' but I need 'z'

What can be the solution to get the previous letter similarly? And what can be the reason as its not working?

Answer 1

I could solve in this way. How is it? The cons is that it only can handle uppercase right now. Some more work can also fix that.

<?php
function get_previous_letter($string){
    $last = substr($string, -1);
    $part=substr($string, 0, -1);
    if(strtoupper($last)=='A'){
        $l = substr($part, -1);
        if($l=='A'){
            return substr($part, 0, -1)."Z";
        }
        return $part.chr(ord($l)-1);
    }else{
        return $part.chr(ord($last)-1);
    }
}
echo get_previous_letter("AAAAAA");
?>

CODEPAD