在类和函数中使用PHP读取/输出JSON

Question

I normally get all JSON data using Jquery however I currently need to do it using only PHP.

Essentially this is how I normally get and output it with Jquery: (Snippet, not whole code)

$.post('getdata.php', {uid:uid} , function(data){
    if(data){   
    $.each(data, function(key, data) {
    $('#div #span-'+key).html(data);
    });

}

} , 'json')

Where uid is the value passed to php for use in querying the database.

And this is the php back end: (Again just a snippet of the JSON section)

while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
    $ret["ID"]       = $row['id'];
    $ret["username"] = $row['username'];
    $ret["email"]    = $row['email'];
    $ret["age"]      = $row['age'];
    echo json_encode($ret);
}

And obviously on the output page along with jquery I initiate the class and function:

$class = new retrieveData();
$class->userDetails();

Then to output the individual parts of the array where I want I would create a span with the same unique key for the particular array part as set out in jquery.

How would I go about converting the jquery part of this into PHP?

Answer 1

So if im understanding you you just want to rework the whole ajax side to sending off a request from the server:

$ch = curl_init($theUrlThatReturnsTheData);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, array('uid' => $uid));
curl_setopt($ch, CURLOPT_POST, true);
$jsonData = curl_exec($ch);

$data = json_decode($jsonData);

Now do whatever it is you need to do with json... assuming from your jquery fragment thats something like this:

<div id="<?php echo $uid ?>">
   <?php foreach($data as $key => $value): ?>
       <span id="span-<?php echo $key ?>">
         <?php echo $value ?>
       </span>
   <?php endforeach; ?>
</div>