dsds661730652211 2015-02-28 20:37
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如何替换html标签内的值？

I want to replace element content with content which is definded in $tagsReplace array but have problem with preg_replace, my current ode:

$tagsReplace = array(
    'header' => 'header',
    'tag1' => 'this is tag1',
    'tag2' => 'this is tag2',
    'tag3' => 'this is tag3',
    'footer' => 'footer',
); 

$content = '
<!DOCTYPE html>
<hthml>
<header data-edit="true" data-tag-id="header"></header>
<div data-edit="true" data-tag-id="tag1"></div>
<div data-edit="true" data-tag-id="tag2"></div>
<div data-edit="true" data-tag-id="tag3"></div>
<footer data-edit="true" data-tag-id="footer"></footer>
</html>
';

$dom = new DOMDocument();
libxml_use_internal_errors(true);
$dom->loadHTML($content);
$xpath = new DomXpath($dom);

foreach ($xpath->query('//*[@data-edit="true"]') as $rowNode) { 
    $tagID = $rowNode->getAttribute('data-tag-id');
    $content = preg_replace('/(<div.*?data-edit="true"[^>]*>)(.*?)(<\/div>)/i', '$1'. $tagsReplace[$tagID] . '$3', $content);
}
echo $content;

What i want is to get output like that:

<!DOCTYPE html>
<hthml>
<header data-edit="true" data-tag-id="header">header</header>
<div data-edit="true" data-tag-id="tag1">this is tag1</div>
<div data-edit="true" data-tag-id="tag2">this is tag2</div>
<div data-edit="true" data-tag-id="tag3">this is tag3</div>
<footer data-edit="true" data-tag-id="footer">footer</footer>
</html>

Current output is:

 <!DOCTYPE html>
<hthml>
<header data-edit="true" data-tag-id="header"></header>
<div data-edit="true" data-tag-id="tag1">footer</div>
<div data-edit="true" data-tag-id="tag2">footer</div>
<div data-edit="true" data-tag-id="tag3">footer</div>
<footer data-edit="true" data-tag-id="footer"></footer>
</html>

Soo all elements which contain atribute data-edit="true" and data-tag-id has to get content inside them replaced by tagid value which is definded in arra $tagsReplace.

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6条回答 默认 最新

  • doublel83422 2015-03-01 00:02
    关注

    Because you are specifying div in your preg_match pattern and we know that the first element starts with header so it won't be matched so simply replace the "div" at the beginning of the preg_match pattern with (.*?) to match header and even other words. this :

    $content = preg_replace('/(<div.?data-edit="true"[^>]>)(.*?)(</div>)/i', '$1'. $tagsReplace[$tagID] . '$3', $content);

    becomes:

    $content = preg_replace('/(<(.*?) data-edit="true"[^>]>)(.?)(</div>)/i', '$1'. $tagsReplace[$tagID] . '$3', $content);

    Another option is available you can use preg_replace_callback(pattern,function,subject) to do what you want magically, here is a solution that worked for me : 

    $content = '
<!DOCTYPE html>
<hthml>
<header data-edit="true" data-tag-id="header"></header>
<div data-edit="true" data-tag-id="tag1"></div>
<div data-edit="true" data-tag-id="tag2"></div>
<div data-edit="true" data-tag-id="tag3"></div>
<footer data-edit="true" data-tag-id="footer"></footer>
</html>
';

$pattern = '/<(.+) data-edit="true" data-tag-id="(.*)"(.*?)>(.*?)<\/(.+)>/';
$another = preg_replace_callback($pattern, function($matches){
    $tagsReplace = array(
        'header' => 'header1',
        'tag1' => 'this is tag1',
        'tag2' => 'this is tag2',
        'tag3' => 'this is tag3',
        'footer' => 'footer',
    ); 
    return '<'.$matches[1].' data-edit="true" data-tag-id="'.$matches[2].'"'.$matches[3].'>'.$tagsReplace[$matches[2]].'<\/'.$matches[5].'>/';
}, $content);
# before the replacement 
print_r($content);
echo '
';
// another holds the content after replacement 
print_r($another);
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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