dongyuan9892 2014-07-20 07:35
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将表单输入插入到数据库中,当为空时不插入为NULL

I have a form and everything works well. However when I escape the input using mysqli real_escape_string, if the input was left blank by the user, it enters blank in the database and not as NULL. here is the code I have for the variable.

    $website = '"'.$mysqli->real_escape_string($_POST['website']).'"';

The variables that are not escaped , ie a variable that is numeric and has only 7 chars appears NULL if nothing is input by the user.

Not sure what to do and Google has not been helpful.

Thanks,

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  • dtqysxw4659 2014-07-20 07:43
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    Just check the value like:

    $website = "NULL";
    
    if (isset($_POST['website']))
      $website = "'" . $mysqli->real_escape_string($_POST['website']) . "'";
    

    .. insert to db

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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