将Marshall JSON Slice转换为有效JSON

Question

I'm building a REST API using Golang but I'm having some troubles trying to correctly Marshalling a Json Slice. I've been scratching my head for a while now, even after looking to several questions and answer and on the web.

Essentially, I have a Redis client that called after a call -X GET /todo/ spits up a slice of todos

[{"content":"test6","id":"46"} {"content":"test5","id":"45"}] //[]string

Now, I want to return a given Response based on the fact that I found todos or not, so I have a Struct like

type Response struct {
    Status string
    Data []string
}

Then, If I found some todos I just Marshal a json with

if(len(todos) > 0){
    res := SliceResponse{"Ok", todos}
    response, _ = json.Marshal(res)
}

And, In order to remove unnecessary \ inside the response, I use bytes.Replace like

response = bytes.Replace(response, []byte("\\"), []byte(""), -1)

Finally, getting

{
   "Status" : "Ok",
   "Data" : [
              "{"content":"test6","id":"46"}",
              "{"content":"test5","id":"45"}"
    ]
}

As you can see each " before each { and after each }, excluding the first and the last ones, are clearly wrong. While the correct JSON would be

{
    "Status": "Ok",
    "Data": [{
        "content ": "test6",
        "id ": "46"
    }, {
        "content ": "test5",
        "id ": "45"
    }]
}

I successfully managed to get them off by finding their index and trim them off and also with regex but I was wondering.

Is there a clean and better way to achieve that?

Answer 1

Whenever possible you should marshal from go objects that match your desired json. I'd recommend parsing the json from redis:

type Response struct {
    Status string
    Data   []*Info
}

type Info struct {
    Content string `json:"content"`
    ID      string `json:"id"`
}

func main() {
    r := &Response{Status: "OK"}
    for _, d := range data {
        info := &Info{}
        json.Unmarshal([]byte(d), info)
        //handle error
        r.Data = append(r.Data, info)
    }
    dat, _ := json.Marshal(r)
    fmt.Println(string(dat))
}

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