获取Golang正则表达式中括号内的所有子字符串

Question

I want to get all the substrings inside all parentheses in go using Regex.

As an example for the string "foo(bar)foo(baz)golang", i want "bar" and "baz"

in python i can do re.findall("(?<=\()[^)]+(?=\))", "foo(bar)foo(baz)golang")

How to do it in go?

Answer 1

go's regexp package does not support zero width lookarounds. You can leverage captured grouping with the regexp.FindAllStringSubmatch() function:

package main

import (
    "regexp"
    "fmt"
)

func main() {
    str := "foo(bar)foo(baz)golang"
    rex := regexp.MustCompile(`\(([^)]+)\)`)
    out := rex.FindAllStringSubmatch(str, -1)

    for _, i := range out {
        fmt.Println(i[1])
    }
}

outputs:

bar
baz

---

The Regex \(([^)]+)\):

• \( matches literal (

• ([^)]+) matches substring upto next ) and put the match in a captured group, here you can use non-greeedy match .*?\) too

• \) matches literal )

---

Go playground demo