dongliuzhuan1219 2017-06-08 22:11
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二进制字符串转换为unicode

I'm not 100% sure why my binary string to unicode isn't working..can anyone point out the issue or help me patch it? Also the reason why i chunk out the binary is that it is too large for ParseInt to handle. See the playground link below for an example.

func binToString(s []byte) string {
    var counter int
    chunk := make([]byte, 7)
    var buf bytes.Buffer
    for i := range s {
        if i%8 == 0 {
            counter = 0
            if i, err := strconv.ParseInt(string(chunk), 2, 64); err == nil {
                buf.WriteString(string(i))
            }
        } else {
            chunk[counter] = s[i] //i know i can use modulus here too but i was testing and an counter was easier to track and test for me
            counter++
        }
    }
    return buf.String()
}

It either seems to miss a character or add an character (or two) on conversion.

Here is a playground link showing an example of the function not working as expected.

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1条回答 默认 最新

  • doumei2023 2017-06-08 22:17
    关注

    Your function could be implemented in a simpler, more efficient manner:

    func binToString(s []byte) string {
        output := make([]byte, len(s)/8)
        for i := 0; i < len(output); i++ {
            val, err := strconv.ParseInt(string(s[i*8:(i+1)*8]), 2, 64)
            if err == nil {
                output[i] = byte(val)
            }
        }
        return string(output)
    }
    

    https://play.golang.org/p/Fmo7I-rN3c

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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