dongzongzi0379 2019-04-15 14:18
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更改类型后获取地址

I am new to Go and I'm trying to find a convenient way from a developers perspective to get an address of an object after changing type.

Consider these two new types:

type specialString string
type nestedStruct struct {
    name *specialString
}

The canonical way I have found for filling in the nestedStruct is this:

str := "James"
specStr := specialString(str)
nested := nestedStruct{
    name: &specStr,
}

Is there a way to omit the declaration of specStr, which is then only used in one place? I tried this, but it triggers an syntax error (what is the logical reason for that?):

//Syntax error
nested := nestedStruct{
    name: &specialString(str),
}

Any help would be appreciated.

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2条回答 默认 最新

  • duanliang2017 2019-04-15 14:24
    关注

    You cannot take the address of an arbitrary operation, including a type conversion. For details, see How can I store reference to the result of an operation in Go?; and Find address of constant in go.

    You can omit one of the local variables if you convert the string literal:

    specStr := specialString("James")
    nested := nestedStruct{
        name: &specStr,
    }
    

    If you already have a variable of string type and you want to omit the second variable (of specialString type), then take the address of the existing string variable, and convert it to *specialString:

    str := "James"
    nested = nestedStruct{
        name: (*specialString)(&str),
    }
    

    Try these examples on the Go Playground.

    If you want to omit the local variable, see this answer for options: How do I do a literal *int64 in Go?

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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