duanhuoyao7011 2016-02-19 02:45
浏览 974
已采纳

在struct golang中打印一个struct

I want to print a certain item within a struct, that is within a struct. Example:
Pretend I have made up a blueprint struct, and are making an new one
Pretend I have a myshapes struct, that contains a title, # of circles, and squares

car := blueprints{
dots: 5,
lines: 25,
shapes: []myshapes{
    myshapes{
        title:"car #1",
        circles:5,
        squares:7,
    },
    myshapes{
        title:"car #2",
        circles:2,
        squares:14,
    },
}

How do I print:

title:"car #1"
circles:5
squares:7
title:"car #2"
circles:2
squares:14
  • 写回答

1条回答 默认 最新

  • dsoxcj7276 2016-02-19 03:03
    关注

    The example below shows how you'd print a particular field value of a struct:

    type child struct {
        name string
        age int
    }
    
    type parent struct {
        name string
        age int
        children child
    }
    
    func main() {
        family := parent{
            name: "John",
            age: 40,
            children: child{
                name: "Johnny",
                age: 10,
            },
        }
    
        fmt.Println(family.children.name); // Prints "Johnny"
    }
    

    The code above would print "Johnny", which is a value of a struct within the parent struct. The code doesn't make much sense, however, because the field is children, yet there is only ever able to be one child as its value.

    Let's leverage slices. Now that we know how to print a particular value, all we would need for your case is to loop over a slice and print the same way we did above.

    We can do that like this:

    type child struct {
        name string
        age int
    }
    
    type parent struct {
        name string
        age int
        children []child
    }
    
    func main() {
        family := parent{
            name: "John",
            age: 40,
            children: []child{
                child{
                    name: "Johnny",
                    age: 10,
                },
                child{
                    name: "Jenna",
                    age: 7,
                },
            },
        }
    
        for _, child := range family.children {
            fmt.Println(child.name);
        }
    }
    

    The above example will pront "Johnny" and "Jenna".

    You can use a similar pattern to what I showed above in your own code to loop through your structs and print whatever value your heart desires :)


    Keep in mind, there are many ways to loop through things. For example, all the following loops would print "Johnny" and "Jenna" from the examples above.

    for _, child:= range family.children{ // Prints "Jonny" and "Jenna"
        fmt.Println(child.name); 
    }
    
    for i, _ := range family.children{ // Prints "Jonny" and "Jenna"
        fmt.Println(family.children[i].name);
    }
    
    for i := 0; i < len(family.children); i++ { // Prints "Jonny" and "Jenna"
        fmt.Println(family.children[i].name);
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题:最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面,并且报了如下错误,尝试过换显卡驱动,但是好像不行
  • ¥15 没有证书,nginx怎么反向代理到只能接受https的公网网站
  • ¥50 成都蓉城足球俱乐部小程序抢票
  • ¥15 yolov7训练自己的数据集
  • ¥15 esp8266与51单片机连接问题(标签-单片机|关键词-串口)(相关搜索:51单片机|单片机|测试代码)
  • ¥15 电力市场出清matlab yalmip kkt 双层优化问题
  • ¥30 ros小车路径规划实现不了,如何解决?(操作系统-ubuntu)