如何获得一天中的秒数[关闭]

Question

How to get seconds of day (1 - 86400) in Go?

Just like http://joda-time.sourceforge.net/apidocs/org/joda/time/base/AbstractDateTime.html#getSecondOfDay()

Update/Clarifications

• Wanted equivalent of the joda/SecondOfDay in golang
• Expected to start at 0 and 86400 at end of the day
• Required when rewriting in golang a java opensource function which in turn is using joda/secondOfDay
• Googled '24 hour to seconds' to get 86400
• While asking question I could only think of now.Unix()-yesterdayMidnight.Unix() and the simple accepted answer didn't come to my mind
• Obviously didn't think about Daylight Saving
• Wanted to see if there is some built in function or popular/standard library

Answer 1

Note: This function returns the nominal number of seconds of day in the (0 - 86399) range. If you're looking for the "number of seconds elapsed since midnight", which may not be in (0 - 86399) range due to daylight saving time, please see @icza's answer.

Update: Please note also that the question refers to Joda Time implementation, which, according to Joda Time getSecondOfDay on DST switch day, seems to correspond to the nominal number of seconds implementation (as in my answer below) as opposed to the "number of seconds elapsed since midnight" (as in @icza's answer).

package main 

import (
    "fmt"
    "time"
)

func getSecondOfDay(t time.Time) int {
    return 60*60*t.Hour() + 60*t.Minute() + t.Second()
}

func main() {
    t := time.Now()
    fmt.Println(getSecondOfDay(t))
}