Problem Description
A peak number is defined as continuous digits {D0, D1 … Dn-1} (D0 > 0 and n >= 3), which exist Dm (0 < m < n - 1) satisfied Di-1 < Di (0 < i <= m) and Di > Di+1 (m <= i < n - 1).
A number is called bi-peak if it is a concatenation of two peak numbers.
The score of a number is the sum of all digits. Love8909 is crazy about bi-peak numbers. Please help him to calculate the MAXIMUM score of the Bi-peak Number in the closed interval [A, B].
Input
The first line of the input is an integer T (T <= 1000), which stands for the number of test cases you need to solve.
Each case consists of two integers “A B” (without quotes) (0 <= A <= B < 2^64) in a single line.
Output
For the kth case, output “Case k: v” in a single line where v is the maximum score. If no bi-peak number exists, output 0.
Sample Input
3
12121 12121
120010 120010
121121 121121
Sample Output
Case 1: 0
Case 2: 0
Case 3: 8
