weixin_33730836 2015-06-15 15:18 采纳率: 0%
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Ajax Post错误Chrome

I'm looking to send my form details through ajax, but every time I hit Submit button, I get the error

 POST http://192.***.**.***:****/api/csl net::ERR_CONNECTION_TIMED_OUT


 m.ajaxTransport.send @ jquery.min.js:4
m.extend.ajax @ jquery.min.js:4
(anonymous function) @ index.html:278
m.event.dispatch @ jquery.min.js:3
m.event.add.r.handle @ jquery.min.js:3
m.event.trigger @ jquery.min.js:3
(anonymous function) @ jquery.min.js:3
m.extend.each @ jquery.min.js:2
m.fn.m.each @ jquery.min.js:2
m.fn.extend.trigger @ jquery.min.js:3
m.each.m.fn.(anonymous function) @ jquery.min.js:4
(anonymous function) @ index.html:223
m.event.dispatch @ jquery.min.js:3
m.event.add.r.handle @ jquery.min.js:3

and

 Uncaught SyntaxError: Unexpected end of input on index line :1 

Here's the code where I'm having issues

$.ajax({
            type: "POST",
            dataType: "json",
            //contentType: "application/x-www-from-urlencoded; charset=UTF-8",
            url: 'http://192.***.**.***:**/api/csl',
            data: source,
            success: function (data) {
                console.log("in ajax");
                var resultsList = data;
                var source = $('#renderCalculation').html();
                var template = Handlebars.compile(source);
                calcTable.html(template(resultsList));
                $('#tblCalc td:nth-child(2)').each(function(d, e) {
                    $(e).text("$" + parseFloat($(this).text()).formatMoney(2)); 
                });
            },
            error: function (error) {
                jsonValue = jQuery.parseJSON(error.responseText);
            }
        });
    });

i got error from browser side

  • 写回答

1条回答 默认 最新

  • weixin_33690963 2015-06-15 16:03
    关注

    Apart from other error, You're leftover a });

    评论

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