AJAX传递表单数据

Question

I am trying to figure out why this is not working. Here is the sub-set of my form that looks like this:

   <input type="hidden" id="gift_id3" name="giver3gift_id" value="925"></td>
   <tr id="tr3">
       <td>
            <select class="type" id="type3" name="giver3paymenttype_val">
             <option value="1" SELECTED>Check</option>
             <option value="2">Cash</option>
             <option value="3">ACH</option>
             <option value="4">In Kind Donation</option>
          </select>
       </td>
       <td><input type="text" class="refnum" id="refnum3" name="giver3ref_num" value="2147483647"></td>
       <td><input type="text" class="amount" id="amount3" name="giver3amount" value="25.00" onBlur="this.value=formatCurrency(this.value)"></td>
       <td>
            <select class="type" id="type3" name="giver3taracct_val">
             <option value="1" SELECTED>General Fund</option>
             <option value="2">Building Fund</option>
             <option value="3">Missions Fund</option>
          </select>
       </td>
       <td><input type="checkbox" id="void3" name="giver3void">
   </tr>

Here is my AJAX:

var $inputs = $("#dialog-editgiving :input");
var parameters = [];                  

$inputs.each(function() {
   parameters[this.name] = $(this).val();
});

$.ajax({
   url : "./scripts/form_process/update_giving.php",
   type: "POST",
   data : {parameters:parameters},
   success: function(data, textStatus, jqXHR)
         {
           alert(data);
         },
   error: function(jqXHR, textStatus, errorThrown)
         {
           alert(errorThrown);
          }
});

Here is my update_giving.php file

<?php

foreach ($_POST as $key => $value) {
 echo "Field ".htmlspecialchars($key)." is ".htmlspecialchars($value)."<br>";
}

?>

When I look through the $inputs array, I get the the values that are submitted in the form. Then it is handed off to the "./scripts/form_process/update_giving.php" script, I get nothing in the POST object.

Do I have something incorrect in my AJAX request?

Answer 1

instead of this code

var $inputs = $("#dialog-editgiving :input");
var parameters = [];                  

$inputs.each(function() {
   parameters[this.name] = $(this).val();
});

use

var paramerter = $( '#dialog-editgiving' ).serialize();

for fetching all input from the form..

and fetch data in update_giving.php file as yoy fetch in normal php function for example

$_POST['giver3taracct_val'];

i hope this code will help you.