零零乙 2015-10-12 13:10 采纳率: 33.3%
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PHP Loop JSON ajax成功

i have a problem about looping throught json output on ajax success. this is my code :

<?php
    $product = mysqli_query($con,select * from product LIMIT 3);
    while ($dataproduct = mysqli_fetch_assoc($product) {

    echo json_encode(array(

            "product" => $dataproduct['product']
    ));

    } 
?>

$.ajax({
    type        : "GET", 
    url         : test.php, 
    dataType    : "json",
    success     : function(data) {
               $.each(data, function() {
                   $.each(this, function(k, v) {
                        $("ul").html(data.product);

                  });
                });
            }
});

<ul>
    <li></li>
</ul>

how to make that "ajax success looping . so i can make an output to "ul" element?

what's wrong with my code?

  • 写回答

3条回答 默认 最新

  • weixin_33737134 2015-10-12 13:32
    关注

    Try following, it should work for you:-

    <?php
        $product = mysqli_query($con,select * from product LIMIT 3);
        $temp = array();
        while ($dataproduct = mysqli_fetch_assoc($product) {
    
        $temp[] = $dataproduct['product'];
    }
    echo json_encode($temp);
    
    ?>
    
    $.ajax({
        type        : "GET", 
        url         : test.php, 
        dataType    : "json",
        success     : function(data) {
                   $.each(data, function(k,v) {
                            $("ul").html(v);
    
                      });
                    });
                }
    });
    
    <ul>
        <li></li>
    </ul>
    
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