PHP JSON输出的结构

Question

this is continued from another question i asked: Listing out JSON data?

my search only returns 1 item, im pretty sure the problem lies somewhere in my php, im not too sure if im adding to the array properly, or it could be the javascript wich you can see on the above link, but i doubt it.

my php code:

function mytheme_ajax_response() {
  $search = $_GET["search_text"];
  $result = db_query("SELECT nid FROM {node} WHERE title LIKE '%s%' AND type = 'product_collection'", $search);

  $noder = array();
  while ($record = db_fetch_object($result)) {
 $noder[] = $record;
  }

  $matches = array();
 $i = 0;
  foreach ($noder as $row) {
    $node = node_load($row->nid);
    $termlink = db_fetch_object(db_query("SELECT tid FROM {term_node} WHERE nid = %d", $row->nid));
    $matches[$i]['title'] = $node->title;
 $matches[$i]['link'] = $termlink->tid;
  }
 ++$i;
 $hits = array();
 $hits['matches'] = $matches;
  print json_encode($hits);
  exit();
}

Answer 1

You appear to be incrementing your $i variable AFTER the foreach loop. Therefore, $i is always 0 throughout your loop, so you are always setting the title and link values for $matches[0].