weixin_33725270 2015-02-11 16:43 采纳率: 0%
浏览 34

Ajax中的功能不起作用

I am trying to learn Ajax/JavaScript and I can not seem to get my search to work. It is meant to return partial names but returns nothing at all

    <html>
    <head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js></script>
    <script type="text/javascript">
    function getName(value) {
        $.post("searchbar.php", {partialName:value},function(data))
            $("#results").html(data);
    }
    </script>
    </head>
    <body>
    <input type="text" onkeyup="getName(this.value)"/>
    <br>
    <div id="results"></div>
    </body>
</html>

php file:

<?php
include "header.php";

$partialName = $_POST['partialName'];

$name = mysql_query("SELECT username FROM grpgusers WHERE username LIKE '%$partialName%'");
while($names = mysql_fetch_array($name)){
    echo "<div>".$names['username']."</div>";
}

?>

could some one please help me out on where I am going wrong?

  • 写回答

3条回答 默认 最新

  • 旧行李 2015-02-11 16:48
    关注

    you are missing braces, change to:

    function getName(value) {
        $.post("searchbar.php", {partialName:value},function(data) {
            $("#results").html(data);
        });
    }
    

    Plus, missing a quote in

    jquery.min.js ></script>
                 ^ right there
    

    change that to jquery.min.js"></script>

    评论

报告相同问题?

悬赏问题

  • ¥35 平滑拟合曲线该如何生成
  • ¥100 c语言,请帮蒟蒻写一个题的范例作参考
  • ¥15 名为“Product”的列已属于此 DataTable
  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题:最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面,并且报了如下错误,尝试过换显卡驱动,但是好像不行
  • ¥15 自己瞎改改,结果现在又运行不了了
  • ¥15 链式存储应该如何解决
  • ¥15 没有证书,nginx怎么反向代理到只能接受https的公网网站