HttpClient 模拟登录 Cookie问题

Question

问题描述：向登录地址发起POST请求，提交登录验证信息，提示登录成功后发起另一个请求，返回提示“未登陆，请重新登陆”。
我这里用了同一个 HttpClient 实例，不知为何？

DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPos("http://members.dota2.com.cn/dologin");
java.util.List nvps = new ArrayList();
nvps.add(new BasicNameValuePair("username", "username"));
nvps.add(new BasicNameValuePair("passwd", "password"));
nvps.add(new BasicNameValuePair("rand", yzm));

httpPost.setEntity(new UrlEncodedFormEntity(nvps));

HttpResponse response = httpclient.execute(httpPost);
int statusCode = response.getStatusLine().getStatusCode();
if (statusCode == 200) {
     HttpEntity entity = response.getEntity();
     String result = EntityUtils.toString(entity);
     JSONObject json = JSONObject.fromObject(result);
     System.out.println("登录系统返回信息："+json.toString());
}
HttpPost httpPost = new HttpPost("http://event21.dota2.com.cn/dota2/activation/vipTester!contend.action");
java.util.List nvps = new ArrayList();
nvps.add(new BasicNameValuePair("r", String.valueOf(Math.random())));
httpPost.setEntity(new UrlEncodedFormEntity(nvps));

HttpResponse response = httpclient.execute(httpPost);

int statusCode = response.getStatusLine().getStatusCode();
if (statusCode == 200) {
     HttpEntity entity = response.getEntity();
     String result = EntityUtils.toString(entity);
     JSONObject json = JSONObject.fromObject(result);
     System.out.println("RETURN DATA : " + json.toString());
}

Answer 1

你可以用fiddler监视一下请求，不行登陆之后把cookie取出来然后再发另一个请求之前把cookie再放进去。。。