2 xiaonewbie xiaonewbie 于 2014.06.26 11:51 提问

C++课程设计老师说我没有用到类 求指教这段代码要怎么修改加上类

#include
#include
#include
using namespace std;
const double pi = 3.14159265;
const double e = 2.718281828459;
const int SIZE = 1000;

typedef struct node//为了处理符号而建立的链表(如: 1+(-2))
{
char data;
node *next;
}node;

typedef struct stack_num//存储 数 的栈
{
double *top;
double *base;
}stack_num;

typedef struct stack_char//存储 运算符号 的栈
{
char *top;
char *base;
}stack_char;

stack_num S_num;//定义
stack_char S_char;//定义
char fu[18] = {'\n', ')', '+', '-', '*', '/', '%', '^',
'Q', 'L', 'C', 'S', 'T', 'c', 's', 't', '('};
int compare[1000];//表现出各运算符号的优先级
double shu[1000];//存储 "数" 的数组
double dai_result;//运算的结果,是为了处理 M 运算(简介函数里有M的定义)
int biao = 0;//和dia_result 一样,为了处理 M 运算
char line[SIZE];//输入的所要计算的表达式

void init()//初始化
{
compare[fu[0]] = -2;//用数字的大小表现出符号的优先级
compare[fu[1]] = -1;
compare[fu[2]] = 2;
compare[fu[3]] = 2;
compare[fu[4]] = 4;
compare[fu[5]] = 4;
compare[fu[6]] = 4;
compare[fu[7]] = 5;
for(int i = 8; i <= 15; i++)
compare[fu[i]] = 6;
compare[fu[16]] = 7;

S_num.base = (double*)malloc(sizeof(double)*SIZE);//为栈开辟空间
S_char.base = (char*)malloc(sizeof(char)*SIZE);//同上
S_num.top = S_num.base;
S_char.top = S_char.base;

}

void push_num(double n)//数字进栈
{
* ++S_num.top = n;
}

void push_char(char c)//运算符号进栈
{
* ++S_char.top = c;
}

double pop_num()//数字出栈
{
double m = *S_num.top;
S_num.top--;
return m;
}

char pop_char()//运算符号出栈
{
char cc = *S_char.top;
S_char.top--;
return cc;
}

char get_top_char()//得到运算符号的栈中最顶端的运算符号
{
return *S_char.top;
}

double operate(double y, char c, double x)//对两个数计算(含是双目运算符:如 , / 等等)
{
double r;
if(c == '-')
r = x - y;
else if(c == '+')
r = x + y;
else if(c == '/' && y != 0)
r = x / y;
else if(c == '
')
r = x * y;
else if(c == '^')
{
r = 1;
for(int i = 1; i <= y; i++)
r *= x;
}
else if(c == '%')
{
int r0 = (int)x % (int)y;
r = double(r0);
}
return r;
}

double operate_one(double one, char cc)//对一个数运算(含单目运算符:如log(L), sin(S) 等等)
{
double r;
if(cc == 'Q')
r = sqrt(one);
else if(cc == 'C')
r = cos(one);
else if(cc == 'S')
r = sin(one);
else if(cc == 'T')
r = tan(one);
else if(cc == 'c')
r = acos(one);
else if(cc == 's')
r = asin(one);
else if(cc == 't')
r = atan(one);

return r;

}

double operate_L(double a, double b, char dian)//求对数的值
{
double r = log(b) / log(a);
return r;
}

double compute()//对整个表达式的计算
{
char c;//表示运算符号
int p = 0;//用于shu[++p], 先初始化
int i, j;

init();//进行初始化

push_char('\n');
line[strlen(line)] = '\n';
line[strlen(line)+1] = '\0';
if(biao)
    push_num(dai_result);//把运算的结果先进栈, 在这个结果的基础上继续进行运算
biao = 0;
for(i = 0; line[i] != '\0';)//把表达式中的数字字符串转化成可计算的数字
{
    int flag = 0;
    int flag1 = 1;//标记是否是运算符号
//  int flag2 = 1;//标记是否出现'_';
    double h = 0;
    int ge;//位数
    int biao_dian = 0;//是否是小数的类型

    while(1)
    {
        flag1 = 1;
        for(j = 0; j <= 16; j++)
        {
            if(line[i] == fu[j])
            {
                flag1 = 0;
                break;
            }
        }
        if(line[i] == '_')
        {
            break;
        }
        if(line[i] == '.')
        {
            i++;
            ge = 0;
            biao_dian = 1;
        }
        if(line[i] == 'P')
        {
            shu[++p] = pi;
            i++;
            break;
        }
        if(line[i] == 'E')
        {
            shu[++p] = e;
            i++;
            break;
        }
        if(flag1)
        {
            h = h * 10 + (line[i] - '0');
            flag = 1;
            i++;
            if(biao_dian)
                ge++;
        }
        else
            break;
    }
    if(flag)
    {
        if(biao_dian)
        {
            int r = 1;
            for(int k = 1; k <= ge; k++)
                r *= 10;
            h /= r;
        }
        shu[++p] = h;//把转化而来的数字存于数组
    }
    if(line[i] == '+')
        shu[++p] = -1;
    else if(line[i] == '-')
        shu[++p] = -2;
    else if(line[i] == '*')
        shu[++p] = -3;
    else if(line[i] == '/')
        shu[++p] = -4;
    else if(line[i] == '%')
        shu[++p] = -5;
    else if(line[i] == '^')
        shu[++p] = -6;
    else if(line[i] == 'Q')
        shu[++p] = -7;
    else if(line[i] == 'L')
        shu[++p] = -8;
    else if(line[i] == 'C')
        shu[++p] = -9;
    else if(line[i] == 'S')
        shu[++p] = -10;
    else if(line[i] == 'T')
        shu[++p] = -11;
    else if(line[i] == 'c')
        shu[++p] = -12;
    else if(line[i] == 's')
        shu[++p] = -13;
    else if(line[i] == 't')
        shu[++p] = -14;
    else if(line[i] == '(')
        shu[++p] = -15;
    else if(line[i] == ')')
        shu[++p] = -16;
    else if(line[i] == '\n')
        shu[++p] = -17;
    i++;
}
i = 1;
while(shu[i] != -17 || get_top_char() != '\n')
{
    double m = shu[i];

    if(m >= 0)
    {
        push_num(m);
        i++;
    }
    else
    {
        if(m == -1)
            c = '+';
        else if(m == -2)
            c = '-';
        else if(m == -3)
            c = '*';
        else if(m == -4)
            c = '/';
        else if(m == -5)
            c = '%';
        else if(m == -6)
            c = '^';
        else if(m == -7)
            c = 'Q';
        else if(m == -8)
            c = 'L';
        else if(m == -9)
            c = 'C';
        else if(m == -10)
            c = 'S';
        else if(m == -11)
            c = 'T';
        else if(m == -12)
            c = 'c';
        else if(m == -13)
            c = 's';
        else if(m == -14)
            c = 't';
        else if(m == -15)
            c = '(';
        else if(m == -16)
            c = ')';
        else if(m == -17)
            c = '\n';
        char ch = get_top_char();//得到最顶端运算符号
        if(compare[ch] < compare[c])//运算符号级别的比较
        {
            push_char(c);
            i++;
        }
        else if(ch == '(' && c == ')')
        {
            pop_char();
            i++;
        }
        else if(compare[ch] >= compare[c] && ch != '(' && ch != '\n')
        {
            if(ch == 'Q' || ch == 'C' || ch == 'S'|| ch == 'T'
                || ch == 'c' || ch == 's' || ch == 't')
            {
                double one = pop_num();
                char dian = pop_char();
                push_num(operate_one(one, dian)); 
            }
            else if(ch == 'L')
            {
                double one_L = pop_num();
                double two_L = pop_num();
                char dian = pop_char();
                push_num(operate_L(two_L, one_L, dian));
            }
            else
            {
                double x = pop_num();
                double y = pop_num();
                char dian = pop_char();
                if(dian == '/' && x == 0)//判断是否除了"零"
                {
                    cout<<"由于您除了零,结果将是错误的"<<endl;
                }
                push_num(operate(x, dian, y));//把进行一次计算的结果入栈
            }
        }
        else
        {
            push_char(c);
            i++;
        }
    }
}
double result = pop_num();//得到结果

return result;

}

int check_kuohao()//检查表达式括号是否匹配
{
int i, f = 0;
int kuo[SIZE], key = 1;

memset(kuo, 0, sizeof(kuo));
for(i = 0; line[i] != '\0'; i++)
{
    if(line[i] == '(')
        kuo[++f] = 1;
    else if(line[i] == ')')
    {
        if(kuo[f] == 1)
        {
            kuo[f] = 0;
            f--;
        }
        else
        {
            key = 0;
            break;
        }
    }
}
if(key && f == 0)
    return 1;
else
    return 0;

}

int check_char()//检查运算符号是否合法(如: 1 +* 4)
{
int i, ge;
for(i = 0; line[i] != '\0'; )
{
ge = 0;
while(line[i] == '+' || line[i] == '-' || line[i] == '*'
|| line[i] == '/' || line[i] == '%' || line[i] == '^'
|| line[i] == 'Q' || line[i] == 'L' || line[i] == 'S'
|| line[i] == 'C' || line[i] == 'T' || line[i] == 's'
|| line[i] == 'c' || line[i] == 't')
{
ge++;
i++;
}
i++;
}
if(ge >= 3)
return 0;
else
return 1;
}

void output(double result)//打出结果
{
printf("所得结果是: ");
cout<<result<<endl;
}

void check()//检查表达式是否合法
{
void introduce();
char cc;//决定计算器按哪种功能进行计算
double result;//结果
void input();//定义
if( check_kuohao() && check_char() )//看是否合法, 合法则计算
{
result = compute();
output(result);
cout<<"输入一个字符'M'或'D'或'F', 决定是否继续: "< while(cin>>cc)
{
if(cc == 'M')
{

system("cls");
introduce();
printf("您上次所得结果为: ");
cout<<result<<endl;
cout<<"在上次计算结果的基础上, 请继续输入想计算的表达式"<<endl;

            dai_result = result;
            biao = 1;

            input();//输入表达式
            break;
        }
        else if(cc == 'D')
        {
            system("cls");
            introduce();
            cout<<"计算器已清零, 请输入您所要计算的表达式"<<endl;
            input();//输入表达式
            break;
        }
        else if(cc == 'F')
        {
            system("cls");
            cout<<"计算器关闭, 谢谢使用!"<<endl;
            break;
        }
        else
        {
            cout<<"所输入字符无效, 请输入一个字符'M'或'D'或'F'!"<<endl;
            continue;
        }
    }
}
else//不合法,分两种不合法
{
    if(check_kuohao() == 0 && check_char() == 1)
    {
        cout<<"您所输入的表达式括号不匹配, 请重新输入:"<<endl;
        input();//输入表达式
    }
    else
    {
        cout<<"您所输入的表达式不合法, 请重新输入:"<<endl;
        input();//输入表达式
    }
}

}

void tackle_fuhao()//处理负号
{
node root, *head, *p, *q, *p1;
root = head = new node;
head->next = NULL;
int i;
for(i = 0; line[i] != '\0'; i++)//建立链表
{
p = new node;
p->data = line[i];
p->next = head->next;
head->next = p;
head = p;
}
// delete p;
q = (node
)malloc(sizeof(node));
head = root;
if(root->next->data == '+' || root->next->data == '-')//处理第一个字符
{
p = new node;
p->data = '0';
p->next = head->next;
head->next = p;
}
if(root->next != NULL)
{
for(q = root->next; q; q = q->next)
{
if(q->data == '(' && (q->next->data == '-' || q->next->data == '+'))
{
p = new node;
p->data = '0';
p->next = q->next;
q->next = p;
}
}
}
// delete q;
p1 = new node;
int qi = -1;
for(p1 = root->next; p1; p1 = p1->next)
{
line[++qi] = p1->data;
}
line[++qi] = '\0';
}

void input()//输入
{
cin>>line;
if(biao == 0)
tackle_fuhao();//处理负号
check();//检查表达式是否合法
}

void introduce()//对计算器的符号功能的简要介绍
{

cout<<"计算器简要介绍"<<endl;
cout<<"C(cos) S(sin) T(tan) a(arccos) c(arcsin) "<<endl;
cout<<"7 8 9 / on t(arctan) "<<endl;
cout<<"4 5 6 * % L(log)"<<endl;
cout<<"1 2 3 - M(M+) Q(sqrt) "<<endl;
cout<<"0 . + ^(乘方) F(off) Enter(=) "<<endl;
cout<<"对于对数输入 L2_5 表示以2为底5的对数"<<endl;
cout<<"M(在前面结果的基础上继续计算,如:上次结果为10,现输入+10.5*2)"<<endl;
cout<<"D(清零并继续输入)"<<endl;
cout<<"F(计算机关闭)"<<endl;
cout<<"输入 P 就代表输入圆周率, 输入 E 代表输入自然对数"<<endl<<endl;
}

void print()
{
cout<<" 欢迎使用本计算器"<<endl;
cout<<"请输入 on 打开计算器"<<endl;
}

void if_start()//是否启动计算器
{
string start;

print();

while(cin>>start)
{
    if(start != "on")
    {
        cout<<"您所输入的字符无效, 请按照介绍的继续输入:"<<endl;
        continue;
    }
    else
        break;
}
if(start == "on")

introduce();//对计算器的简要介绍
cout<<"现在,请输入您所要计算的表达式"<<endl;
input();//输入所要计算的表达式

}

int main()
{
if_start();//调用是否启动计算器函数

return 0;

}

Csdn user default icon
上传中...
上传图片
插入图片
准确详细的回答,更有利于被提问者采纳,从而获得C币。复制、灌水、广告等回答会被删除,是时候展现真正的技术了!