grc0108 2015-02-11 06:31 采纳率: 100%
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json转换问题,求解求搭救。。。。。。。。。

[
{
wFrom: {
fLatitude: "114.057868",
fLongitude: "22.543099",
fName: "深圳市"
},
wTo: {
tLatitude: "37.6173",
tLongitude: "55.755826",
tName: "Moscow"
},
wValue: "31",
wkey: "深圳市",
wproperties: "bag"
},
{
wFrom: {
fLatitude: "116.681972",
fLongitude: "23.354091",
fName: "汕头市"
},
wTo: {
tLatitude: "37.6173",
tLongitude: "55.755826",
tName: "Moscow"
},
wValue: "24",
wkey: "汕头市",
wproperties: "Baby Toys"
}
];
上面个数组怎么遍历构造出下面这种结构的数据:
var geodata = { "Moscow":[37.6173,55.755826],
"深圳市":[114.057868,22.543099],
"汕头市":[116.681972,23.354091] };
求高手指点啊

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3条回答 默认 最新

  • danielinbiti 2015-02-11 07:26
    关注
     <!DOCTYPE html>
    <html>
    <body>
    
    <script>
    var json=[ 
    { 
    wFrom: { 
    fLatitude: "114.057868", 
    fLongitude: "22.543099", 
    fName: "深圳市" 
    }, 
    wTo: { 
    tLatitude: "37.6173", 
    tLongitude: "55.755826", 
    tName: "Moscow" 
    }, 
    wValue: "31", 
    wkey: "深圳市", 
    wproperties: "bag" 
    }, 
    { 
    wFrom: { 
    fLatitude: "116.681972", 
    fLongitude: "23.354091", 
    fName: "汕头市" 
    }, 
    wTo: { 
    tLatitude: "37.6173", 
    tLongitude: "55.755826", 
    tName: "Moscow" 
    }, 
    wValue: "24", 
    wkey: "汕头市", 
    wproperties: "Baby Toys" 
    } 
    ];
    function get(){
       var obj;
       var wFrom;
       var wTO;
       var geodata ={};
       for(var i=0;i<json.length;i++){
          obj = json[i];
          wFrom = obj['wFrom'];
          wTO = obj['wTo'];
          geodata[obj.wkey]=[wFrom.fLatitude,wFrom.fLongitude];
          geodata[wTO.tName]=[wTO.tLatitude,wTO.tLongitude];
       }
       return geodata;
    }
    var geodata  = get();
    alert(geodata );
    </script>
    
    
    </body>
    </html>
    
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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