就编写一程序,用于统计从键盘输入的字符串中的元音字母(a,A,e,E,i,I,o,O,u,U)的个数。
输入
每行输入一字符串,串长不超过255。
输出
输出对应字符串中元音字母的个数。
样例输入 Copy
abcio efgaeio ak akkkksd
样例输出 Copy
3 5 2
#include<stdio.h>
int main()
{
int count, i;
char str[225];
static char s[11] = { 'a','e','i','o','u','A','E','I','O','U'};
i = 0;
while ((str[i] = getchar()) != '\n')
i++;
str[i] = '\0';
count = 0;
for (i = 0; str[i] != '\0'; i++)
if( str[i] == 'a'|| str[i] == 'e' || str[i] == 'i' || str[i] == 'o' || str[i] == 'u' || str[i] == 'A' || str[i] == 'E' || str[i] == 'I' || str[i] == 'O' || str[i] == 'U' )
count++;
printf("%d", count);
}