关于StringTokenizer中分隔符后面为空，该如何处理？

Question

public class DBNameTest {

/**
 * 验证登陆的用户名密码
 * @param args
 * @return 
 * @throws ClassNotFoundException 
 * @throws SQLException 
 */
public static void main(String[] args) throws ClassNotFoundException, SQLException{
    //定义数据库驱动器
    String DRIVER = "com.mysql.jdbc.Driver";
    //加载数据库驱动器
    Class.forName(DRIVER);
    //定义数据库的链接
    String URL = "jdbc:mysql://192.168.1.18:3306/cuihao?useUnicode=true&characterEncoding=UTF-8";
    String Users = "root";
    String Passw = "root";
    Connection con = null;
    try {
        con = DriverManager.getConnection(URL, Users, Passw);
        con.setAutoCommit(false);
    } catch (SQLException e) {
        e.printStackTrace();
    }
    //PrepareStatement执行动态的SQL语句，并返回他所生成结果的对象
    Statement st = null;
    //ResultSet数据库结果集的数据表
    ResultSet rs = null;
    //输入
    Scanner scanner = new Scanner(System.in);
    //构造ArrayList用来存储从数据库中取出的数据
    ArrayList<NameTest> list = new ArrayList<NameTest>();
    try {
        System.out.println("请以“用户名:密码”格式输入：");
        String upString = scanner.next();
        //分割
        **StringTokenizer stoString = new StringTokenizer(upString, ":");
        String uString = stoString.nextToken();
        String pString = stoString.nextToken();**
        //判断输入是否为空
        if((null != uString)&&(null != pString)){
            //查询
            String selectString = "select * from logins";
            st = con.createStatement();
            rs = st.executeQuery(selectString);
            while(rs.next()){
                String name = rs.getString("username");
                String pass = rs.getString("passwords");
                NameTest nt = new NameTest(name, pass);
                list.add(nt);
            }
            for(Iterator<NameTest> iterator = list.iterator(); iterator.hasNext();){
                NameTest n = iterator.next();
                if(uString.equals(n.getUsernameString())){
                    System.out.println("用户名正确！");
                }else {
                    System.out.println("用户名错误！");
                }
                if(pString.equals(n.getPasswordString())){
                    System.out.println("密码正确！");
                }else {
                    System.out.println("密码错误！");
                }
            }
        }else {
            System.out.println("用户名或密码不能为空！");
        }
    } catch (SQLException e) {
        con.rollback();
        e.printStackTrace();
    }
    //关闭
    con.commit();
    rs.close();
    st.close();
    con.close();
}

}

数据库中用户名密码为 :"hao""123"，当输入“hao:”时程序抛异常。
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(StringTokenizer.java:349)
at com.ch.test15.DBNameTest.main(DBNameTest.java:53)
我该怎样处理才能避免此异常，求解答！

Answer 1

http://www.cnblogs.com/newsouls/p/4038273.html
数据库中没有记录，迭代器异常