webservice“服务器未能识别 HTTP 头 SOAPAction 的值: 。”

Question

Service service = new Service();
Call call = (Call) service.createCall();
String szUrl = "http://XXX/sendsms.asmx";
call.setTargetEndpointAddress(new java.net.URL(szUrl));
call.setOperationName(new QName("http://XXX/sendsms.asmx", "SendSmsService"));
call.addParameter("content", XMLType.XSD_STRING, ParameterMode.IN);
call.addParameter("phone", XMLType.XSD_STRING, ParameterMode.IN);
call.addParameter("uid", XMLType.XSD_STRING, ParameterMode.IN);
call.setUseSOAPAction(true);
call.setReturnType(org.apache.axis.encoding.XMLType.SOAP_STRING);
String ret = (String) call.invoke(new Object[] { "开始测试：这是内容；", "XXX", "2" });
System.out.println(ret);

Answer 1

你这还是报错的啊