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关注with a as( select rank() over (partition by 商店 order by 商店,sum(价钱) desc) as rowid, 商店,sum(价钱) as 价钱和,备注 from 产品 group by 备注,商店), b as( select 商店,价钱和,备注 from a where rowid = 1), c as( select 商店,sum(价钱和) as 卖出价钱和 from a group by 商店) select c.商店,c.卖出价钱和,b.备注 as 卖出价钱最高货物,b.价钱和 as 卖出最高价格货物价格之和 from c inner join b on c.商店 = b.商店本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报

