我又来问问题了,(自学JS没人请教也是尴尬,好像找个师傅啊),下面是问题 谢谢了
这是图片轮播代码,麻烦大家,在浏览器打开看下,这样能说清楚问题
<!DOCTYPE html>
<html>
<head lang="en">
<meta charset="UTF-8">
<title></title>
<style type="text/css">
*{margin:0; padding:0;}
li{list-style:none; background:#f60; float:left; margin-right:10px; border-radius:8px; padding:2px 6px; cursor:pointer;
text-align:center;}
ul{width:140px; position:absolute; bottom:20px; right:20px;}
.main{width:720px; height:450px; margin:0 auto; position:relative; left:0; top:100px; border:5px green solid;}
.abc{width:720px; height:106px; margin:auto; margin-top:120px; background:#ccc; text-align:center;}
.abc img{margin-right:10px; width:144px; height:90px; margin-top:8px;}
</style>
</head>
<body>
<div class="main">
<img src="1.jpg" id="tp"/>
<ul>
<li id="dianji1" onmousemove="showA(1)">1</li>
<li id="dianji2" onmousemove="showA(2)">2</li>
<li id="dianji3" onmousemove="showA(3)">3</li>
<li id="dianji4" onmousemove="showA(4)">4</li>
</ul>
</div>
<div class="abc">
<img src="1.jpg" id="pic1" onmousemove="showB(1)"/>
<img src="2.jpg" id="pic2" onmousemove="showB(2)"/>
<img src="3.jpg" id="pic3" onmousemove="showB(3)"/>
<img src="4.jpg" id="pic4" onmousemove="showB(4)"/>
</div>
<script type="text/javascript">
var gh=1;
var mc=1;
var tup=['http://a1.qpic.cn/psb?/V11aE2wE1DtywZ/I93pSorEWp54MpVhMNDEuPoY6sWU2y4sel7zcxygX0U!/b/dAMAAAAAAAAA&bo=0ALCAdACwgEBCS4!&rf=viewer_4',
'http://a2.qpic.cn/psb?/V11aE2wE1DtywZ/gYhbpYS80HxerKihb7FP8Xz6oBPopJd4Dv.Or6VNIJM!/b/dFgAAAAAAAAA&bo=0ALCAdACwgEBACc!&rf=viewer_4',
'http://a2.qpic.cn/psb?/V11aE2wE1DtywZ/kC2U6ySDDMDiJi7Dmk5TtdH7S609Ny4mhTFEO96rNjg!/b/dGQAAAAAAAAA&bo=0ALCAdACwgEBACc!&rf=viewer_4',
'http://a1.qpic.cn/psb?/V11aE2wE1DtywZ/vC9QsPEduvx6GCOIpq80bXh0t3oUAIzT2smAfm*lrwY!/b/dB4AAAAAAAAA&bo=0ALCAdACwgEBACc!&rf=viewer_4'];
document.getElementById('dianji1').style.backgroundColor='black';
document.getElementById('dianji1').style.color='white';
document.getElementById('pic1').style.border='3px #f60 solid';
function showA(a){
var dianjigh=document.getElementById('dianji'+gh);
var dianjia=document.getElementById('dianji'+a);
dianjigh.style.backgroundColor='#f60';
dianjigh.style.color='black';
document.getElementById('pic'+gh).style.border='none';
dianjia.style.backgroundColor='black';
dianjia.style.color='white';
document.getElementById('tp').src=tup[a-1];
document.getElementById('pic'+a).style.border='3px #f60 solid';
gh=a;
}
function showB(c){
var dianjimc=document.getElementById('dianji'+mc);
var dianjic=document.getElementById('dianji'+c);
dianjimc.style.backgroundColor='#f60';
dianjimc.style.color='black';
document.getElementById('pic'+mc).style.border='none';
dianjic.style.backgroundColor='black';
dianjic.style.color='white';
document.getElementById('tp').src=tup[c-1];
document.getElementById('pic'+c).style.border='3px #f60 solid';
mc=c;
}
</script>
</body>
</html>
鼠标放在 1,2,3,4上后,上面对应的图片切图,下面的小图片带边框
鼠标放在下面的小图片上,上面的大图也会切图
(只设置了onmousemove并没onmouseout)
那么问题来了
假如你鼠标放在2那,下面对应的第二个图会出现边框,然后你把鼠标移到下面第三个图上,结果下面第三个图也出现边框了,一下两个边框
同理鼠标一开始放在下面第二个图上,然后上面对应的数字2背景变黑,这个时候,鼠标移到上面数字3上面.同时3的背景色也变黑了 ,
怎么解决这个问题呢,加上onmouseout可以吗
怎样才能让第一个函数工作的时候清除第二个函数带来的效果,第二个函数工作的时候清除第一个函数带来的效果?
真心求教////
