2 qq 22555381 qq_22555381 于 2015.07.15 19:10 提问

IOS swift 字符串解析成NSArry类型

[{"Android":[{"ID":31,"TN":"天天","Date":"2015-03-17","Des":"315活动"},{"ID":32,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":33,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":34,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":35,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":36,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":38,"TN":"天天","Date":"2015-03-17","Des":"315"},{"ID":22,"TN":"天天","Date":"2015-01-31","Des":"sdaSDASD"},{"ID":23,"TN":"天天","Date":"2015-01-31","Des":"fgsdfgsdfg"},{"ID":7,"TN":"天天","Date":"2015-01-17","Des":"课外活动"},{"ID":8,"TN":"天天","Date":"2015-01-17","Des":"sun sun"},{"ID":9,"TN":"天天","Date":"2015-01-17","Des":"美不胜收,应接不暇"},{"ID":11,"TN":"天天","Date":"2015-01-17","Des":"fgsdjfgsdgfb"},{"ID":12,"TN":"天天","Date":"2015-01-17","Des":"frvxfsdds"},{"ID":13,"TN":"天天","Date":"2015-01-17","Des":"hahahahahhh"},{"ID":14,"TN":"天天","Date":"2015-01-17","Des":"盛开的菊花"},{"ID":15,"TN":"天天","Date":"2015-01-17","Des":"灯塔"},{"ID":16,"TN":"天天","Date":"2015-01-17","Des":"八仙花"},{"ID":18,"TN":"天天","Date":"2015-01-17","Des":"郁金香"},{"ID":19,"TN":"天天","Date":"2015-01-17","Des":"企鹅"},{"ID":20,"TN":"天天","Date":"2015-01-17","Des":"沙漠"},{"ID":21,"TN":"天天","Date":"2015-01-17","Des":"水母"},{"ID":3,"TN":"天天","Date":"2015-01-07","Des":"cvxcvxzcvcvzxcvzzcccccccccccccccc"},{"ID":4,"TN":"天天","Date":"2015-01-07","Des":"dfsadfsadfdfsdfsd"}]}]
这个NSString数据类型的字符串如何转换成一个NSArry数组?在安卓中是通过getJSONbject("Android")解析出来的

4个回答

zhao18933
zhao18933   2015.07.16 09:22
已采纳

最后输出的就是NSArray

         let data = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: true)
        if data != nil {
            let obj: AnyObject? =  NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers, error: nil)
            if obj!.isKindOfClass(NSArray.classForCoder()) {
                print(obj)
            }

        }
guwei4037
guwei4037   Ds   Rxr 2015.07.15 19:19
qq_22555381
qq_22555381 我想把这个string弄成NSArray类型,那样我就可以得到里面的字典进行取值啊,问题是我现在不能将它变成数组啊
2 年多之前 回复
qq_22555381
qq_22555381 我想把这个string弄成NSArray类型,那样我就可以得到里面的字典进行取值啊,问题是我现在不能将它变成数组啊
2 年多之前 回复
u012320146
u012320146   2015.07.18 00:11

objectmapper 在github上搜这个库

u012320146
u012320146   2015.07.18 00:15

只需写2个class,class1包含一个名为andriodid的属性,类型为[class2],就是数组啦,class2包含那几个属性desc这些。

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