//逆序输出一个数
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int reverse(int number);
int main()
{
int number;
printf("Please input a number: ");
scanf("%d",&number);
int new_number = reverse(number);
printf("%d\n",new_number);
system("pause");
return 0;
}
int reverse(int number)
{
int number_new = 0;
int size_of_number = 0;
int temp = number;
while (temp / 10)
{
size_of_number++;
temp /= 10;
}
for (int i = 1,j = size_of_number; i <= size_of_number, j >= 1; i++, j--)
{
number_new += (int)pow((double) 10,i-1)*(number % (int)pow((double)10,j));
number -= (int)pow((double)10,j) * (number % (int)pow((double)10,j));
}
return number_new;
}
不用数组输出一个数的逆序,这个程序问题所在
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3条回答 默认 最新
- mifit 2015-10-31 06:21关注
int reverse(int number){
int tem = number;
int result = 0;
while ( tem > 0) {
result *= 10;
result += tem % 10;
tem /= 10;
}
return result;
}解决 无用评论 打赏 举报