程序片段如下:
var data_1;
$.post("getdata.php",function(string_1){
data_1 = string_1;
});
为什么string_1的内容无法被获取呢?_
要想获取其内容,应该如何做呢?麻烦指点下!
getdata.php:
<?php_
$con = mysql_connect('localhost','root');
mysql_select_db('my_db',$con);
$sql = 'SELECT * FROM data';
$result = mysql_query($sql);
//将数据存入数组
$sql_data = array();
while($row = mysql_fetch_array($result)){
$sql_data[] = $row['data'];
}
echo json_encode($sql_data);
?>