$('#dg').datagrid({
url:'',
pagination:true,
toolbar:'#tb',
pageSize: 30,
striped: true,
checkOnSelect: true,
singleSelect:false,
rownumbers:false,
columns:[
[
{field:'id',align:'center',checkbox:'true',formatter:function(v,o){
return o==null?"":o.perfix;
}
},
{field:'perfix',title:'号段前缀',width:170,align:'center'},
{field:'type',title:'运营商类型',width:170,align:'center',formatter:function(v,o){
return getYYSType(v);
}},
]
],
onLoadSuccess:function(data){console.log(data)},
onLoadError: function () {
$.messager.alert("页面读取出错");
}
});
<form id="gridForm" action="" method="">
<table id="dg" title="号段管理">
</table>
</form>
请问这样写后用jquery的serialize方法序列化gridForm表单为什么取不到id的值?