python如何从zip压缩包内过滤出指后缀文件

Question

比如压缩包中有.jpg、.txt、.doc而我只想打印出.txt的文件列表，如何实现，初学pyhton还请有经验的朋友帮忙指导，我的简单代码如下：
#coding = utf-8

-*- coding: cp936 -*-

import os
import fnmatch
import zipfile

def iterfindfiles(path, fnexp):
for root, dirs, files in os.walk(path):
for filename in fnmatch.filter(files, fnexp):
yield os.path.join(root, filename)

for filelist in iterfindfiles("F:\pythinfile", "*.zip"):
print filelist #打印zip文件列表
print '#'*5
z = zipfile.ZipFile(filelist, "r"）
for file in z.namelist( ):
print file #打印zip文件中文件的列表
需要在打印出所有文件信息中过滤出指定类型的文件，如何添加代码？谢谢

Answer 1

import os
import fnmatch
import zipfile
import re
def iterfindfiles(path, fnexp):
for root, dirs, files in os.walk(path):
for filename in fnmatch.filter(files, fnexp):
yield os.path.join(root, filename)
result=""
for filelist in iterfindfiles("D:\Temporary", "*.zip"):
z = zipfile.ZipFile(filelist, "r")
for file in z.namelist():
result=result+file+"\n"
print "以下内容是压缩包所包含文件："
print result+"\r\n"
unicodepage=result.decode("utf-8")
myItems=re.findall("([\w\d]*?.txt)",unicodepage,re.S)
items=[]
print "以下是获取所有以.txt结束的文本"
for item in myItems:

items.append(item.replace("\r\n",""))

print items