请教一下这段代码哪里出错了？

Question

 #include <stdio.h>
#include <stdlib.h>

typedef int Elemtype;
typedef struct node{
  Elemtype elem;
  struct node *next;
}*top;
int m=sizeof(struct node);

struct node *Push(struct node *top,Elemtype x){
  struct node *p;
  p=(struct node *)malloc(m);
  p->next=top;
  top=p;
  p->elem=x;
  return top;
}

struct node *Pop(struct node *top,Elemtype &x){
  if(top==NULL) return 0;
  struct node *p;
  p=top;
  x=p->elem;
  top=top->next;
  delete p;
  return top;
}

Elemtype GetTop(struct node *top){
  if(top==NULL) return -1;
  int x=top->elem;
  return x;
}

int main(){
  struct node *p;
  int x=0,y=0;
  Push(p,2);
  Push(p,34);
  Pop(p,x);
  printf("%d",x);
  y=GetTop(p);
  return 0;
}

然后用g++编译通过，但是运行程序时出现提示：

 LinkStack(14073,0x7fff7729d300) malloc: *** error for object 0x7fff55c40b00: pointer being freed was not allocated
*** set a breakpoint in malloc_error_break to debug
Abort trap: 6

请问这是怎么回事？

Answer 1

 #include <stdio.h>
#include <stdlib.h>

typedef int Elemtype;
typedef struct node{
  Elemtype elem;
  struct node *next;
};

struct node * top;
int m=sizeof(struct node);

struct node *Push(Elemtype x){
  struct node *p;
  p=(struct node *)malloc(m);
  p->next=top;
  top=p;
  p->elem=x;
  return top;
}

struct node *Pop(Elemtype &x){
  if(top==NULL) return 0;
  struct node *p;
  p=top;
  x=p->elem;
  top=top->next;
  delete p;
  return top;
}

Elemtype GetTop(){
  if(top==NULL) return -1;
  int x=top->elem;
  return x;
}

int main(){
  top=(struct node *)malloc(sizeof(struct node));
  int x=0,y=0;
  Push(2);
  Push(34);
  Pop(x);
  printf("%d",x);
  y=GetTop();
  return 0;
}