在一个popupwindow中如何从一个editText box中获取input。我用了2种方法,一种是使用layout inflator。
另一种方法没有使用layout inflator,尽管我在box中输入信息,但是获得""或者null。
返回""的方法:
View inflatedView = getLayoutInflater().inflate(R.layout.login_popup, null);
EditText usernameInput = (EditText) inflatedView.findViewById(R.id.username_login_input);
EditText passwordInput = (EditText) inflatedView.findViewById(R.id.password_login_input);
final String usernameString = usernameInput.getText().toString();
final String passwordString = passwordInput.getText().toString();
返回 null 的方法:
EditText usernameInput = (EditText) findViewById(R.id.username_login_input);
EditText passwordInput = (EditText) findViewById(R.id.password_login_input);
final String usernameString = usernameInput.getText().toString();
final String passwordString = passwordInput.getText().toString();
我想从 login_popup.xml 中获取,这不是从一个 activity 中生成的。
代码是:
LayoutInflater layoutInflater =
(LayoutInflater) getBaseContext().getSystemService(LAYOUT_INFLATER_SERVICE);
View popupView = layoutInflater.inflate(R.layout.login_popup, null);
ppw = new PopupWindow(popupView, LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT, true);
ViewGroup parentLayout = (ViewGroup) findViewById(R.id.title_page_layout);
// set the position and size of popup
ppw.showAtLocation(parentLayout, Gravity.CENTER, 10, 20);