2 qq 32995053 qq_32995053 于 2016.03.19 13:41 提问

C/C++杭电1501题Wooden sticks 求挑错

Description
There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:

(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.

You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).

Input
The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

Output
The output should contain the minimum setup time in minutes, one per line.

Sample Input

3
5
4 9 5 2 2 1 3 5 1 4
3
2 2 1 1 2 2
3
1 3 2 2 3 1

Sample Output

2
1
3

#include
#include

using namespace std;

struct stick
{
int len;
int wei;
bool judge;
}s[10009];

int cmp(stick a,stick b)
{
if(a.len!=b.len)
return a.len else
return a.wei }
int main()
{
int T,n,i,j,time;
cin>>T;
while(T--)
{
cin>>n;
for(i=0;i {
cin>>s[i].len>>s[i].wei;
s[i].judge=true;
}
sort(s,s+n,cmp);
time=0;
int flag_len=s[0].len,flag_wei=s[0].wei,num;
for(i=0;i {
if(s[i].judge==false)continue;
for(j=i,num=0;j {
if(s[j].len>=flag_len&&s[j].wei>=flag_wei)
{
s[j].judge=false;
num++;
}
}
if(num)time++;
for(j=i+1;j<n;j++)
{
if(s[j].judge==true)
{
flag_len=s[j].len;
flag_wei=s[j].wei;
break;
}
}
}
cout<<time<<endl;
}
return 0;
}

1个回答

caozhy
caozhy   Ds   Rxr 2016.03.19 14:25
已采纳
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准确详细的回答,更有利于被提问者采纳,从而获得C币。复制、灌水、广告等回答会被删除,是时候展现真正的技术了!