如何将三角形做成死循环,当输入特殊字符才停止跳出程序??
import java.util.Scanner;
class Trangle {
double A,B,C,area,length;
Trangle (double a,double b,double c)throws TrangleException{
if(a+b<=c||a+c<=b||c+b<=a) throw new TrangleException();
A=a;
B=b;
C=c;
}
public void setABC(double a,double b,double c) throws TrangleException
{if(a+b<=c||a+c<=b||c+b<=a) throw new TrangleException();
A=a;
B=b;
C=c;
}
public double getLength() {
return A+B+C;
}
public double getArea(){
double p;
p=(A+B+C)/2;
area=Math.sqrt(p*(p-A)*(p-B)*(p-C));
return area;
}
}
class TrangleException extends Exception{
TrangleException(){
super("三角形构造失败");
}
}
public class AreaAndLength
{ public static void main(String args[]) throws Exception
{ try{ int a,b,c;
Scanner s = new Scanner(System.in);
System.out.print("请输入三角形第1个边长(回车继续):");
a = s.nextInt();
System.out.print("请输入三角形第2个边长(回车继续):");
b = s.nextInt();
System.out.print("请输入三角形第3个边长(回车继续):");
c = s.nextInt();
Trangle trangle=new Trangle(a, b, c);
System.out.println("三角形周长:"+trangle.getLength());
System.out.println("三角形面积:"+trangle.getArea());
}catch(Exception e){
System.out.println(e);
}
}
}