Java事物回滚失效，在抛出异常的情况下仍然提交了SQL

Question

private Connection connection;
private Statement pre;

public String set(String goal,String marriage){
return "update info set goal='"+goal+"'where marriage='"+marriage+"'";
}

public void start(){
    String sql="jdbc:mysql://127.0.0.1/student";

    try {
        connection = DriverManager.getConnection(sql,"root","111");
        connection.setAutoCommit(false);
        pre = connection.createStatement();

        pre.executeUpdate(set("配偶","未婚"));
        pre.executeUpdate(set("情人","已婚"));
        pre.executeUpdate(set("包养","学生"));

  if(true)
        throw new SQLException("ni");

        connection.commit();
    } catch (SQLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();

        try {
            connection.rollback();
        } catch (SQLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
    }
}

Answer 1

抛的是什么异常，发一下

if(true)
throw new SQLException("ni");
这个自定义异常，一定会抛出。。。。。但-----它是上抛，相当于方法抛出异常一样，向上级(main方法)抛，所以try-catch中，
不会捕获到你的自定义SQLException("ni");