Java 中将Timestamp 转换成Json后
Timestamp timestamp = Timestamp.valueOf("2016-06-06 12:00:00");
JSONObject jsonObject = JSONObject.fromObject(timestamp);
System.out.println(jsonObject);
输出值为:
'pickdate':{"date":15,"day":1,"hours":12,"minutes":0,"month":1,"nanos":0,"seconds":0,"time":571896000000,"timezoneOffset":-480,"year":88}
问题:如何在jsp页面中使用easy-ui 的datagrid将json格式的时间戳正常显示为:"2016-06-06 12:00:00"???
jsp页面的easy-ui代码为:
var columns = [ [ {
field : 'pickdate',
title : '取件日期',
align : 'center',
width : 100,
formatter: function(value,row,index){
return ????这里改怎么写???;
}
}] ];