代码如下,我将播放器代码渲染到id为divVideo的div.如果播放文件路径正确且存在,一切正常,可以播放.如果播放路径错误或者文件名不存在。则浏览器会一直请求直至崩溃。希望把异常捕获出来,不让他重复去一直请求。用了 try catch 没效果。不知道有什么好办法
var oDiv = document.getElementById("divVideo");
oDiv.innerHTML = " <a href='javascript:void(0);' onclick='videoClose()' style='display: block;text-align: left;'>关闭</a> "
+ " <object type='application/x-shockwave-flash' width='740' height='264' "
+ " wmode='transparent' data='tools/Flvplayer.swf?vcastr_file=../"+obj.name+"&autostart=true'>"
+ " <param name='allowFullScreen' value='true' />"
+ " <param name='movie' value='tools/Flvplayer.swf?vcastr_file=../"+obj.name+"&autostart=true' /> "
+ " <param name='wmode' value='transparent' /> "
+ " <param name='SendErrorEvents' value='true' /> "
+ " <object/> ";
符浏览器控制台错误信息;![图片说明](https://img-ask.csdn.net/upload/201606/17/1466135156_730143.png)![图片说明](https://img-ask.csdn.net/upload/201606/17/1466135313_293188.png)