//Exe2.4 编程求1000以内的所有完数。(完数:除自身外等于其余所有约数的和)
#include <iostream>
using namespace std;
int main(){
int num = 1;
int sum = 0;
for(int i = 1;i <= 1000;i++){
for(int j = 1;j <= 1000;j++){
if(num % j == 0){
sum += j;
if(num == (sum - num)){
cout << num << endl;
}
}
else{
continue;
}
}
sum = 0;
num++;
}
}