关于Python逆向的一个简单问题求助。

Question

下面附上函数代码，求解出flag值 key值已经给出，求帮助啊，逆推过程应该怎么写啊

import base64

def encode(flag):
l1 = []
for a in flag:
l1.append(chr(int(ord(a)) - 10))
l1.reverse()#反向存储

mid = ''.join(list(l1))
key = base64.b64encode(mid)
print key

key = 'YmVVJ2ReT2ZqZVVpWSY=='

上边的代码缩进有点问题 代码在这里http://paste.ubuntu.com/23493247/

Answer 1

import base64
def encode(flag):
tmp_list = []
for a in flag:
tmp_list.append(chr(int(ord(a)) - 10))
tmp_list.reverse()
mid = ''.join(list(tmp_list))
key = base64.b64encode(mid)
return key

def decode(value):
tmp_str = base64.b64decode(value)
lists = list(tmp_str)
lists.reverse()

new_list = []
for x in  lists:
    tmp_x = chr(ord(x) + 10)
    new_list.append(tmp_x)
    new_list.reverse()
new_list.reverse()
print new_list

if name == '__main__':
strs = "123"
value = encode(strs)
ori_str = decode(value)