统计字符串中各字符的个数

Question

#include
#include
int main()
{
char string[50];
int a=0,b=0,c=0,e=0,i;
printf("please input something:\n");
scanf("%s", string);
for(i=0;i<=strlen(string)-1;i++)
{
if(('a'<= string[i]&&string[i]<='z')||('A'<= string[i]&&string[i]<='Z')) a++;
else if(('0'<= string[i])&&(string[i]<='9')) b++;
else if(string[i]==32) c++;
else e++;
}
printf("a=%d\nb=%d\nc=%d\ne=%d\n",a,b,c,e);
return 0; }

这个程序出错了
菜鸟求各位大神解答

Answer 1

scanf（“%s”,string）;