Swagger配置config,转换为doc

Question

public String jsonToAdoc(Map params){
String json = params.get("json");
Swagger20Parser parser = new Swagger20Parser();
try {
Swagger swagger = parser.parse(json);
Swagger2MarkupConfig config = new Swagger2MarkupConfigBuilder()
.withMarkupLanguage(MarkupLanguage.ASCIIDOC)
.withOperationOrdering(OrderBy.NATURAL)
.withOutputLanguage(Language.ZH)
.build();
return Swagger2MarkupConverter.from(swagger).build().toString();
} catch (IOException e) {
e.printStackTrace();
}
return "json有错误";
}
关于Swagger的Swagger2MarkupConfigBuilder这个配置类如何写，还有Swagger2MarkupConverter.from(swagger)这个方法报下面这个错The type io.github.swagger2markup.Swagger2MarkupConverter$Builder cannot be resolved. It is indirectly referenced from required .class files，实在有点不懂，那位兄弟帮帮忙

Answer 1

那位兄弟比较熟悉Swagger的，帮忙看看