请教PHP中JSON字符串取值问题

Question

MYSQL中字段shezhi的内容是

 a:1:{s:4:"sale";a:3:{s:10:"enoughfree";i:1;s:11:"enoughorder";d:123;s:11:"enoughareas";s:0:"";}}

PHP中取值代码是

 'by' => (!(empty($goods['detail_by'])) ? $goods['detail_by'] : $shop['shezhi'])

取得的值是shezhi字段的全部内容，请问如何修改代码，只取123这个值

Answer 1

可以将json转成数组再去取对应的值吧