在配置微信JS-SDK接口的时候,需要在后台动态获得发送请求的页面的url(http://localhost:8080/ConnectTest/GetData.jsp),但我用getRequestURL得到的却是后台文件的地址(http://localhost:8080/ConnectTest/sign),ps:使用过request.getAttribute("javax.servlet.forward.request_uri")但返回的url为null。代码如下
GetData.jsp代码:
<script>
$(document).ready(function(){
$.ajax({
//提交数据的类型 POST GET
type:"Get",
//提交的网址
url:"http://localhost:8080/ConnectTest/sign",
//提交的数据
/* data:form, */
datatype:"json",
success:function(data){
var obj = JSON.parse(data);
var jsonstr = JSON.stringify(obj);
var jsary = eval('('+jsonstr+')');
alert(jsary.url)
alert(location.href.split('#')[0])
wx.config({
debug: true,
appId: 'wx51b7336a2b1cd2d9',
timestamp: 'jsary.timestamp',
nonceStr: 'jsary.nonceStr',
signature: 'jsary.signature',
jsApiList: [
"wx.onMenuShareTimeline"
]
});
wx.ready(function(){
//share to timeline
wx.onMenuShareTimeline({
title: '百度', // 分享标题
link: 'www.baidu.com',
imgUrl: 'https://www.baidu.com/img/bd_logo1.png', // 分享图标
success: function () {
alert("分享成功")
},
cancel: function () {
alert("分享失败")
}
});
});
}
});
});
</script>
Sign.java(http://localhost:8080/ConnectTest/sign):
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try {
String jsapi_ticket = "kgt8ON7yVITDhtdwci0qeXxjVFn7AZ9I21TkQnlxXoQF3VTPc5tRORpvuB_slLD-Xua5sSwuBOrO5ZfMNGJUTA";
String url = request.getRequestURL().toString()+"/";
System.out.println(url);
Map<String, String> ret = sign(jsapi_ticket, url);
sendScResponse(ret, response);
} catch (Exception e) {
e.printStackTrace();
}
}
<-- 中间省略一些不重要的代码-->
private void sendScResponse(Object obj, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/javascript; charset=UTF-8");
response.setCharacterEncoding("UTF-8");
if (obj != null) {
String responseStr = m_gson.toJson(obj);
response.getWriter().write(responseStr);
}
}