编程介的小学生 2017-10-03 14:00 采纳率: 20.5%
浏览 644
已采纳

Keeps Going and Going and ...

Description

Lazy functional languages like Haskell and Miranda support features that are not found in other programming languages, including infinite lists. Consider the following simple (and useful) recursive declaration:
letrec
count n = cons n (count (n+1))
in
count 0

The function cons constructs lists, so the above declaration creates the following structure:

cons 0 (count 1)
= cons 0 (cons 1 (count 2))
= cons 0 (cons 1 (cons 2 ...))
= [0,1,2,...]

Lazy languages can do this because they only evaluate expressions that are actually used. If a program creates an infinite list and only looks at items 2 and 3 in it, the values in positions 0 and 1 are never evaluated and the list structure is only evaluated so far as the fourth node.

It is also possible to use more than one function to build an infinite list. Here is a declaration that creates the list ["even","odd","even",...]:

letrec
even = cons "even" odd
odd = cons "odd" even
in
even

There are also functions that manipulate infinite lists. The functions take and drop can be used to remove elements from the start of the list, returning the (removed) front elements or the remainder of the list, respectively. Another useful function is zip, which combines two lists like the slider on a zipper combines the teeth. For example,

zip (count 0) (count 10) = [0,10,1,11,2,12,...]

Your task is to implement a subset of this functionality.
Input

The first line of input consists of two positive integers, n and m. n is the number of declarations to follow and m is the number of test cases.

Each declaration takes the form name = expr. There are two forms for expr : zip name1 name2 and x0 x1 ... xi name3. In the first case, name is the result of zipping name1 and name2 together. The other case defines the first i + 1 non-negative integers in the list name (where i is at least 0) and name3 is the name of the list that continues it (mandatory--all lists will be infinite).

The test cases take the form name s e, where s and e are non-negative integers, s <= e and e - s < 250.

No line of input will be longer than 80 characters. Names consist of a single capital letter.
Output

For each test case, print the integers in positions s to e of the list name. List elements are numbered starting with 0.
Sample Input

5 3
S = 4 3 2 1 A
O = 1 O
E = 0 E
A = zip E O
Z = zip Z S
A 43455436 43455438
S 2 5
Z 1 10
Sample Output

0 1 0
2 1 0 1
4 4 3 4 2 3 1 4 0 2

  • 写回答

1条回答 默认 最新

  • threenewbee 2017-10-19 11:04
    关注
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 不是,这到底错哪儿了😭
  • ¥15 2020长安杯与连接网探
  • ¥15 关于#matlab#的问题:在模糊控制器中选出线路信息,在simulink中根据线路信息生成速度时间目标曲线(初速度为20m/s,15秒后减为0的速度时间图像)我想问线路信息是什么
  • ¥15 banner广告展示设置多少时间不怎么会消耗用户价值
  • ¥16 mybatis的代理对象无法通过@Autowired装填
  • ¥15 可见光定位matlab仿真
  • ¥15 arduino 四自由度机械臂
  • ¥15 wordpress 产品图片 GIF 没法显示
  • ¥15 求三国群英传pl国战时间的修改方法
  • ¥15 matlab代码代写,需写出详细代码,代价私