我想输出列表a中的子列表x的第二个元素,写了如下代码
x = [1,2,3]
y = [4,5,6]
z = [7,8,9]
a = [x,y,z]
print(a[x[1]])
输出结果却是一组列表,不明白为什么
C:\Python36\python.exe "E:/python code/new_restaurant.py"
[7, 8, 9]
Process finished with exit code 0
我想输出列表a中的子列表x的第二个元素,写了如下代码
x = [1,2,3]
y = [4,5,6]
z = [7,8,9]
a = [x,y,z]
print(a[x[1]])
输出结果却是一组列表,不明白为什么
C:\Python36\python.exe "E:/python code/new_restaurant.py"
[7, 8, 9]
Process finished with exit code 0
x = [1, 2, 3]
y = [4, 5, 6]
z = [7, 8, 9]
a = [x, y, z]
print(a[0][0:]) # 或print(a[0][:])