Hastiness

Question

Problem Description
How many problems did you AC?
When you read this problem, don’t hasty and careless, this is also simple, haha, I didn’t cheat you.
The game over soon, WisKey starts using English begin countdown. He not only have no gene in math, but also bad in English. Fortunately, He met you who have gift in programming. So please help him to translate.

Input
Give you an integer T, output T in English, and note that all of words are lower case. (0<=T<=9999)

Output
One answer One line.
Details see sample.

Sample Input
2034
1234
123
24
0

Sample Output
two thousand and thirty-four
one thousand and two hundred and thirty-four
one hundred and twenty-three
twenty-four
zero

Answer 1

#include///Hastiness
using namespace std;
map M;
map M1;
map M2;
void init()
{
M[1] = "one";
M[2] = "two";
M[3] = "three";
M[4] = "four";
M[5] = "five";
M[6] = "six";
M[7] = "seven";
M[8] = "eight";
M[9] = "nine";
M[0] = "zero";

M1[1] = "ten";
M1[2] = "twenty";
M1[3] = "thirty";
M1[4] = "forty";
M1[5] = "fifty";
M1[6] = "sixty";
M1[7] = "seventy";
M1[8] = "eighty";
M1[9] = "ninety";

M2[0] = "ten";
M2[1] = "eleven";
M2[2] = "twelve";
M2[3] = "thirteen";
M2[4] = "fourteen";
M2[5] = "fifteen";
M2[6] = "sixteen";
M2[7] = "seventeen";
M2[8] = "eighteen";
M2[9] = "nineteen";

}
int main()
{
int t,n,a,b,c,c1,c2,d;
init();
while(~scanf("%d",&n))
{
a=n/1000;
b=n%1000/100;
c1=n%100;
c=c1/10;
d=n%10;
if(a!=0)
{
if(b==0&&c==0&&d==0)
{
cout< continue;
}
else
{
cout }
}
if(b!=0)
{
if(c==0&&d==0)
{
cout printf(" hundred\n");
continue;
}
else
{
cout printf(" hundred and ");
}
}
if(c1>=20)
{
if(d==0)
{
cout< continue;
}
else
{
cout continue;
}
}
if(c1=10)
{
cout<<M2[d]<<endl;
continue;
}
if(c1<10)
{
cout<<M[d]<<endl;
}
}
}