hibernate注解配置一对多并且一方为联合主键

Question

hibernate注解配置单向一对多（配置在一的一方）并且一的一方为联合主键，这个该怎么配置，最好是写一个demo

Answer 1

如下是一个“酒店房间信息表”，以hotelRoomId和hotelId为联合主键。其中配置了“一对多”和“多对一”

package cn.ssms.model;

import java.util.HashSet;
import java.util.Set;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.Table;

@Entity
@Table(name="hotelRoom")
public class HotelRoom{
    private int hotelRoomId;            //客房编号
    private String hotelRoomName;       //房间名称
    private String hotelRoomImage;      //客房图片

    private Hotel hotel;                //属于哪个酒店

    private Set<HotelOrder> hotelOrderSet = new HashSet<HotelOrder>();              //相关的酒店订单的集合
    private Set<HotelRoomDate> hotelRoomDateSet = new HashSet<HotelRoomDate>();     //房间不同日期信息的集合

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Column(name="hotelRoomId")
    public int getHotelRoomId() {
        return hotelRoomId;
    }
    public void setHotelRoomId(int hotelRoomId) {
        this.hotelRoomId = hotelRoomId;
    }
    @Column(name="hotelRoomImage")
    public String getHotelRoomImage() {
        return hotelRoomImage;
    }
    public void setHotelRoomImage(String hotelRoomImage) {
        this.hotelRoomImage = hotelRoomImage;
    }
    @Column(name="hotelRoomName")
    public String getHotelRoomName() {
        return hotelRoomName;
    }
    public void setHotelRoomName(String hotelRoomName) {
        this.hotelRoomName = hotelRoomName;
    }

    @ManyToOne(fetch=FetchType.LAZY,targetEntity=Hotel.class)
    @JoinColumn(name="hotelId")
    public Hotel getHotel() {
        return hotel;
    }
    public void setHotel(Hotel hotel) {
        this.hotel = hotel;
    }
    @OneToMany(cascade=CascadeType.ALL,fetch=FetchType.LAZY,mappedBy="hotelRoom")
    public Set<HotelOrder> getHotelOrderSet() {
        return hotelOrderSet;
    }
    public void setHotelOrderSet(Set<HotelOrder> hotelOrderSet) {
        this.hotelOrderSet = hotelOrderSet;
    }
    @OneToMany(cascade=CascadeType.ALL,fetch=FetchType.LAZY,mappedBy="hotelRoom")
    public Set<HotelRoomDate> getHotelRoomDateSet() {
        return hotelRoomDateSet;
    }
    public void setHotelRoomDateSet(Set<HotelRoomDate> hotelRoomDateSet) {
        this.hotelRoomDateSet = hotelRoomDateSet;
    }
}

有疑问请回复。欢迎采纳，谢谢！