python 正则如何多次匹配？

Question

例如abc1abc2abc3abc
re.findall('abc\w*?abc','abc1abc2abc3abc',re.I)

            结果为['abc1abc', 'abc3abc']
            怎么把abc2abc也提取出来？

Answer 1

我google了下

stackoverflow上有人问过这个问题

https://stackoverflow.com/questions/5616822/python-regex-find-all-overlapping-matches
https://stackoverflow.com/questions/41045008/return-all-overlapping-patterns-using-re-findall-in-python

网站可能需要科学下才能上，我复制了关键的一段

 import re 
s = "123456789123456789"
matches = re.finditer(r'(?=(\d{10}))',s)
results = [int(match.group(1)) for match in matches]
# results: 
# [1234567891,
#  2345678912,
#  3456789123,
#  4567891234,
#  5678912345,
#  6789123456,
#  7891234567,
#  8912345678,
#  9123456789]