小弟 通过myeclipse自动生成的struts的action form jsp 写了一个简单的login 成功
然后想不通过form 只用action 和jsp 重新写个login 一直出错 请知道的朋友解答下
多谢!!!!
代码如下
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>3</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>3</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
structs-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.3//EN" "http://struts.apache.org/dtds/struts-config_1_3.dtd">
<struts-config>
<form-beans >
<form-bean name="aaaaForm" type="org.apache.struts.validator.DynaValidatorActionForm" />
</form-beans>
<global-exceptions />
<global-forwards >
<forward
name="success"
path="/success.jsp"
redirect="true" />
<forward
name="failed"
path="/failed.jsp"
redirect="true" />
</global-forwards>
<action-mappings >
<action
attribute="aaaaForm"
input="/form/aaaa.jsp"
name="aaaaForm"
path="/aaaa"
scope="request"
type="com.yourcompany.struts.action.AaaaAction" />
</action-mappings>
<message-resources parameter="com.yourcompany.struts.ApplicationResources" />
</struts-config>
jsp
<%@ page language="java" import="java.util.*" pageEncoding="GB18030"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'aaaa.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<body>
<form action ="/aaaa">
name :<input type ="text" name="name">
password :<input type ="password" name ="password">
<input type="submit" value="wahaha">
</form>
</body>
</html>
action
public class AaaaAction extends Action {
/*
* Generated Methods
/
/*
* Method execute
* @param mapping
* @param form
* @param request
* @param response
* @return ActionForward
*/
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
if(request.getParameter("name").equals("aaa")&&request.getParameter("password").equals("123")){
return mapping.findForward("success");
}
else
return mapping.findForward("failed");
}
}
多谢了!!!
问题补充:
错误信息 :
输入 用户名和密码后的
HTTP Status 404 - /aaaa
--------------------------------------------------------------------------------
type Status report
message /aaaa
description The requested resource (/aaaa) is not available.
问题补充:
success.jsp failed.jsp
都建了
问题补充:
恩 和INDEX.JSP一个位置
问题补充:
我追踪了 好像不经过action
问题补充:
没有 加我QQ63913838这样太慢了 多谢!!
struts自动生成的action form jsp 和自己创建的 一点小问题
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