目的:我在一个弹出层里再次定义一个弹出层,可是用最后一层的弹出层用parent方法只能获取到最外层的页面;
页面1 main.jsp:
在这里我弹出一个层:
function openMessageWindow(){
var diag = new Dialog("MessageIframe");
diag.Width = 970;
diag.Height = 550;
diag.Title = "MessageBox";
diag.URL = "";
diag.ShowMessageRow = false;
diag.MessageTitle = "163";
diag.Message = "xyz";
diag.ShowButtonRow = false;
//diag.Pos=[10,10];
diag.Modelstatic=false;
diag.show();
}
页面2 MessageBox.jsp即上个层弹出的页面:
function sendMsgWindow2(){
sendMessage = new Dialog("sendMsgIframe");
sendMessage.Width = 620;
sendMessage.Height = 510;
sendMessage.Title = "message";
sendMessage.URL = "";
sendMessage.ShowMessageRow = false;
sendMessage.MessageTitle = "message";
sendMessage.Message = "xyz";
sendMessage.ShowButtonRow = false;
sendMessage.Modelstatic=false;
sendMessage.show();
}
页面三 sendMsgPage.jsp为页面2弹出的层,我在页面三中,用parent获取的对象是页面1的对象,请问怎么才能获取到页面2的对象呢?