langhua9527 2011-08-02 10:28 采纳率: 0%
浏览 471
已采纳

JAVA程序里面怎么测试一个Servlet是否可用

比如说一个SERVLET的地址是
http://www.sina.com.cn/test/servlet
(这个SERVLET是我自己可以修改的)
现在我这里的程序要测试这个连结是否正常
我在JAVA里面的程序应该怎么写才好?
这个还有跨域的问题,不能用AJAX去试
我想在JAVA里面测试

  • 写回答

7条回答 默认 最新

  • fireinjava 2011-08-02 16:43
    关注

    redstarofsleep的没错,我来个完整的
    [code="java"]
    import java.io.IOException;

    import org.apache.commons.httpclient.HttpClient;
    import org.apache.commons.httpclient.HttpStatus;
    import org.apache.commons.httpclient.methods.PostMethod;
    import org.apache.commons.httpclient.methods.StringRequestEntity;

    public class HttpSender {

    public String send(String url,  String request) throws Exception {
    
        String response = null;
        HttpClient httpClient = new HttpClient();
        PostMethod method = new PostMethod(url);
        method.addRequestHeader("charset", "GBK");
        method.addRequestHeader("content-type", "application/x-www-form-urlencoded");
        method.setRequestEntity(new StringRequestEntity(request, null, "GBK"));
    
        try {
            int retcode = httpClient.executeMethod(method);
            if (retcode == HttpStatus.SC_OK) {
                byte[] responseBody = new byte[10240];
                java.io.InputStream istream = method.getResponseBodyAsStream();
                int npos = 0;
                int nread = 0;
                while ((nread = istream.read(responseBody, npos, responseBody.length - npos)) >= 0) {
                    npos += nread;
                    if (npos >= responseBody.length) {
                        byte[] tmpBuf = new byte[npos + 51200];
                        System.arraycopy(responseBody, 0, tmpBuf, 0, npos);
                        responseBody = tmpBuf;
                    }
                }
                response = new String(responseBody, 0, npos);
            } else {
                throw new IOException("发送失败: retcode: " + retcode);
            }
              method.releaseConnection();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return response;
    }
    
    public static void main(String[] args) throws Exception {
        String reqStr = "<?xml version=\"1.0\" encoding=\"GBK\"?><request><params><param><curDate>20101010</curDate></param></params></request>";
        HttpSender sender = new HttpSender();
        String reponse = sender.send("http://www.sina.com.cn/test/servlet", reqStr);
        System.out.println("返回报文"+reponse);
    }
    

    }
    [/code]
    当然,你的web.xml要配置
    [code="java"]

    servlet
    com.xx.YourServlet

    <servlet-mapping>
        <servlet-name>servlet</servlet-name>
        <url-pattern>/servlet</url-pattern>
    </servlet-mapping>
    

    [/code]

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(6条)

报告相同问题?

悬赏问题

  • ¥30 这是哪个作者做的宝宝起名网站
  • ¥60 版本过低apk如何修改可以兼容新的安卓系统
  • ¥25 由IPR导致的DRIVER_POWER_STATE_FAILURE蓝屏
  • ¥50 有数据,怎么建立模型求影响全要素生产率的因素
  • ¥50 有数据,怎么用matlab求全要素生产率
  • ¥15 TI的insta-spin例程
  • ¥15 完成下列问题完成下列问题
  • ¥15 C#算法问题, 不知道怎么处理这个数据的转换
  • ¥15 YoloV5 第三方库的版本对照问题
  • ¥15 请完成下列相关问题!